3x^2-2x-5Subject is factoring quadratic trinomials when a doesn’t =1
Accepted Solution
A:
Answer:(3x-5)(x+1)Step-by-step explanation:For a general polynomial ax^2+bx+c, we need to find two numbers that multiply to ac and add up to b.In this case, we need to find two numbers that multiply to 3*(-5) = -15 and add up to -2. These are 3,-5. Rewrite the polynomial as:3x^2+3x-5x-5And then factor each pair:3x(x+1)-5(x+1) = (3x-5)(x+1)