Which of the following are solutions to the equation below?Check all that apply.(3x + 4)2 = 14

Answer:F and EStep-by-step explanation:[tex](3x+4)^2=14[/tex]We could get rid of the square on the (3x+4) by square rooting both sides:[tex]3x+4=\pm \sqrt{14}[/tex]Now you are left with a linear equation to solve.Subtract 4 on both sides:[tex]3x=-4 \pm \sqrt{14}[/tex]Divide both sides by 3:[tex]x=\frac{-4 \pm \sqrt{14}}{3}[/tex]You could rearrange the numerator using commutative property:[tex]x=\frac{\pm \sqrt{14}-4}{3}[/tex]If you wanted two write the two answers out, you would write:[tex]x=\frac{\sqrt{14}-4}{3} \text{ or } \frac{-\sqrt{14}-4}{3}[/tex].So I see this in F and E.You could separate the fraction:[tex]x=\frac{\sqrt{14}}{3}-\frac{4}{3} \text{ or } -\frac{\sqrt{14}}{3}-\frac{4}{3}[/tex].