Q:

Test the claim that the proportion of men who own cats is smaller than the proportion of women who own cats at the .005 significance level.The null and alternative hypothesis would be:H0:pM=pFH0:pM=pFH1:pMH0:μM=μFH0:μM=μFH1:μM>μFH1:μM>μFH0:pM=pFH0:pM=pFH1:pM>pFH1:pM>pFH0:μM=μFH0:μM=μFH1:μM<μFH1:μM<μFH0:μM=μFH0:μM=μFH1:μM≠μFH1:μM≠μFH0:pM=pFH0:pM=pFH1:pM≠pFH1:pM≠pFThe test is:two-tailedright-tailedleft-tailedBased on a sample of 40 men, 25% owned catsBased on a sample of 40 women, 35% owned catsThe test statistic is: (to 2 decimals)The p-value is: (to 2 decimals)Based on this we:Fail to reject the null hypothesisReject the null hypothesis

Accepted Solution

A:
Answer:The null and alternate hypothesis would beH0:   pm = pf  H1:   pm < pf   Test is left tailedThe test statistic: z = -0.98The p-value: 0.1365We fail to reject the null hypothesisConclusion:  There is not enough evidence to support the claim that the proportion of men who own cats is less than the proportion of women who own catsStep-by-step explanation:The null and alternate hypothesis would beH0:  pm = pf Ha:  pm < pf    because they say that the test claim is the proportion of men is smaller less than the proportion of women.  The null hypothesis always get the statement of equality (the equals sign).  In this case, the alternate hypothesis is the claim.  The test is left tailed because the alternate hypothesis has a <  sign.  It's strictly less than a value, so it's one tailed, and the < or > sign points to the area of rejection, so in this case, it's pointing leftThe test statistic is calculation is attached as a photo  The p-value is found by looking it up on the chart using z = -0.98Since 0.1365 > 0.005, we fail to reject the null hypothesisBecause we fail to reject the null, there is not enough evidence to support the claim